0.0034s^2+0.004s-0.3=125

Solution for 0.0034s^2+0.004s-0.3=125 equation:

0.0034s^2+0.004s-0.3=125

We move all terms to the left:

0.0034s^2+0.004s-0.3-(125)=0

We add all the numbers together, and all the variables

0.0034s^2+0.004s-125.3=0

a = 0.0034; b = 0.004; c = -125.3;
Δ = b2-4ac
Δ = 0.0042-4·0.0034·(-125.3)
Δ = 1.704096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.004)-\sqrt{1.704096}}{2*0.0034}=\frac{-0.004-\sqrt{1.704096}}{0.0068}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.004)+\sqrt{1.704096}}{2*0.0034}=\frac{-0.004+\sqrt{1.704096}}{0.0068}
$